*HOMEWORK+HELP!+*

[[file:ReviewKeySide1.pdf]]


Hey Justin, I'm assuming you mean problems like "find sin 60" for degree measures 30, 60, and 45, we set up the "generic" special right triangle (remember we did those a few weeks ago?) Here is what they look like: (sorry.... can't draw- not at my home computer)

http://www.regentsprep.org/Regents/math/algtrig/ATT2/Pic3060.gif

http://www.regentsprep.org/Regents/math/algtrig/ATT2/Pic4545.gif So if you wanted to find the sin of 60, look at the first one... sin is O/H which means ( rad 3 / 2 ) If you wanted "cos 45" - look at the second triangle. Cos is A/ H so (1/ rad 2 ) .... simplify (multiply top and bottom by rad 2) and you get (rad 2 / 2). Also, look at the answers to the study guide... I showed detail work for these. There's a link on the home page. Did this help?Need more help? Let me know here or come in the morning... there will be a few ppl there. ~Mrs. Bujdei

- i have no idea how to do them. I looked at some that you did on the website Buj, but i'm confused where you got all the numbers from. Justin
 * No calculator problems.**

**SET 27 HELP (or anything else):**

 * Post questions here!**

I'm still a little confused on how to find the sides in a 45.45.90 triangle when they only give you the hypotenuse. For the homework on set 27 number 8. Am I doing this right? It doesnt seem right.

if the hypotenuse is 16. its 45.45.90

16= x√2

16 / √2 = x√2 / √2

16 / √2 = x

16√2 / 2 = x x=8√2

also help with number 10?

Thanks- lizzie

Hi Lizzie, (I moved your post up- makes it easier for people to see). You are absolutely correct on #8! The pattern for 45-45-90 is x - x - x √2. So side, side, side TIMES √2. You go backwards when given the hypotenuse, so like you did, you divide by radical 2. For # 10.... you are given the side. To find the hypotenuse, multiply the side by √2. So you have (17 √2) √2 = 17√4 = 17 (2) = 34 Make sense??

Any other questions? anyone? :) ~Mrs. Bujdei **

**HELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLOHELLO**
I hear there are issues..... pick a problem. Let's talk it through......


 * 21?



Ok, I will try to explain a little here. Let's start with the easy one.... z. z is a leg of the big triangle, so use pyth thm. ( 5^2 + z^2 = 14^2) You end up with z = 13.08

So there's 14, and one part of it is y. So let the other little part be 14-y. Next, we can match legs and hypotenuse.

I did hyp / little leg = hyp / little leg

So, 14 / 13.08 = 13.08 / (14-y)

What do you think??? Let me know if you need more help. ~ Mrs. Bujdei PS- please post any more questions you have HERE!!!!

1267581637126758163712675816371267581637126758163712675816371267581637126758163712675816371267581637 Number 19 please!(: -Kaitlyn



start with y:

long leg / short leg = long leg / short leg y / 4 = 6 / y

then it's all pythagorean thrm. ~ Buj

I get it more now, but i still need a little bit of help like number 23?


 * Can you help me with #22, #29, #30? -Kaitlyn**

same as #20. USE 10, 20, and x. y is pyth theorem. Once you find x, z is pyth thm. What proportion did you get for x??? ~Buj**
 * . [[image:#22.jpg width="210" height="187"]]


 * 29 - Start with z- PYTH thm. we started it in class, and i promised we'd finish it too. once you have z, try using the big triangle ( short leg / hypotenuse) to match with something with y. make sense? ~Buj**

Similar idea for 30 (as for 29). Start with x. Let me know if you need more direction for these.... ~Buj


 * Okay I understand them more. Thank you very much for your help. -Kaitlyn(:

hi there. ~Aaron.

hi. my name is Tom. i don't know how to edit the wiki ~ Tom**